x^2+(2x+10)(2x+10)=20

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Solution for x^2+(2x+10)(2x+10)=20 equation: 



x^2+(2x+10)(2x+10)=20

We move all terms to the left:

x^2+(2x+10)(2x+10)-(20)=0

We multiply parentheses ..

x^2+(+4x^2+20x+20x+100)-20=0

We get rid of parentheses

x^2+4x^2+20x+20x+100-20=0

We add all the numbers together, and all the variables

5x^2+40x+80=0

a = 5; b = 40; c = +80;
Δ = b2-4ac
Δ = 402-4·5·80
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-40}{10}=-4$

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